Tutor applicants have rated the interview process at WyzAnt with 2.3 out of 5 (where 5 is the highest level of difficulty) and assessed their interview experience as 62% positive. To compare, the company-average is 72.5% positive. This is according to Glassdoor user ratings.
Candidates applying for Tutor roles take an average of 8 days to get hired, when considering 15 user submitted interviews for this role. To compare, the hiring process at WyzAnt overall takes an average of 7 days.
Common stages of the interview process at WyzAnt as a Tutor according to 15 Glassdoor interviews include:
Skills test: 32%
Background check: 29%
Phone interview: 14%
Other: 11%
Presentation: 7%
IQ intelligence test: 4%
Drug test: 4%
Here are the most commonly searched roles for interview reports -
I applied online. The process took 4 weeks. I interviewed at WyzAnt in Sep 2023
Interview
Pretty straightforward. When you sign up on the website, they ask you to fill out a tutor title and profile, which they'll review. They give you several attempts to rewrite it if they don't approve it the first time. You can also qualify for subjects by taking a quiz for those subjects.
Interview questions [1]
Question 1
Write your Free Response, detailing your past tutoring or teaching experience, education/degrees, and other qualifications.
I applied online. The process took 3 days. I interviewed at WyzAnt (Irvine, CA) in Jan 2024
Interview
Discussed strategies, students, abilities, concepts, and challenges. Set up brand new zoom accounts on my devices in order to accommodate the software needs of this job position. So far, they have mentioned to me that they plan to offer me the position through email.
I applied online. I interviewed at WyzAnt (Bellefonte, PA) in Jan 2020
Interview
There are some online assessments for various subjects, Calculus, algebra, Statistics, programming (Python, R, SAS, ect). You are asked to finish the assessment in a given time frame, 30 minutes
Interview questions [1]
Question 1
Find the limit of the following equation:
lim (x/e^x) as x goes to infinity